Copper reacts with sulfuric acid according to the following equation:

2H3SO4 + Cu-> CuSO4 + 2H2O + SO2
How many grams of sulfur dioxide are created by this reaction if 14.2 g of copper reacts with 18 g of sulfuric acid?

Well, well, well! Looks like we have a chemical reaction on our hands. Let's do some math and find out how "gram-tastic" this reaction is!

According to the equation, 1 mole of copper (Cu) reacts with 2 moles of sulfur dioxide (SO2). To find the number of moles of copper, we need to divide its mass by its molar mass.

The molar mass of copper (Cu) is approximately 63.5 g/mol. So, 14.2 g of copper is equal to 14.2 g / 63.5 g/mol = 0.2237 mol.

Now, let's take a look at sulfur dioxide (SO2). According to the equation, every 1 mole of copper (Cu) reacts with 1 mole of sulfur dioxide (SO2). Therefore, the number of moles of sulfur dioxide formed will be the same as the number of moles of copper, which is 0.2237 mol.

To find the mass of sulfur dioxide, we multiply the number of moles by its molar mass. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol.

So, the mass of sulfur dioxide produced is 0.2237 mol × 64 g/mol = 14.32 g.

Therefore, approximately 14.32 g of sulfur dioxide are created by this reaction.

Remember, though, this is just an approximation. If you need accurate results, it's best to use some fancy lab equipment instead of relying on a humorous bot like me!

To determine the number of grams of sulfur dioxide produced in the reaction, you need to use stoichiometry.

First, calculate the number of moles of each reactant using their respective molar masses:

Molar mass of copper (Cu) = 63.55 g/mol
Molar mass of sulfuric acid (H2SO4) = 98.09 g/mol

Number of moles of copper:
moles of Cu = mass of Cu / molar mass of Cu
moles of Cu = 14.2 g / 63.55 g/mol
moles of Cu = 0.2238 mol

Number of moles of sulfuric acid:
moles of H2SO4 = mass of H2SO4 / molar mass of H2SO4
moles of H2SO4 = 18 g / 98.09 g/mol
moles of H2SO4 = 0.1834 mol

Next, determine the mole ratio between copper and sulfur dioxide from the balanced equation. Looking at the equation, you can see that 1 mole of copper reacts to produce 1 mole of sulfur dioxide.

Using this ratio, you can calculate the number of moles of sulfur dioxide produced:

moles of SO2 = moles of Cu

moles of SO2 = 0.2238 mol

Finally, calculate the mass of sulfur dioxide produced using its molar mass:

Molar mass of sulfur dioxide (SO2) = 64.06 g/mol

mass of SO2 = moles of SO2 * molar mass of SO2
mass of SO2 = 0.2238 mol * 64.06 g/mol
mass of SO2 = 14.33 g

Therefore, the reaction between 14.2 g of copper and 18 g of sulfuric acid produces 14.33 grams of sulfur dioxide.