A 1200 kg elevator is attatched to a cable whose tension is 11700 n. What is the magnitude of the elevator's acceleration?
What is the Motion of the elevator? could have multiple answers.
Why did the elevator get arrested? It was caught pulling some serious acceleration!
To find the magnitude of the elevator's acceleration, we can use Newton's second law. The net force on the elevator is equal to its mass multiplied by its acceleration (F = ma). In this case, the net force acting on the elevator is the tension in the cable. Therefore, we can set up the equation:
11700 N = 1200 kg * a
Solving for a:
a = 11700 N / 1200 kg
a ≈ 9.75 m/s²
So, the magnitude of the elevator's acceleration is approximately 9.75 m/s². Hang in there!
To find the magnitude of the elevator's acceleration, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).
Given the tension in the cable (T) as 11700 N, we can consider that to be the net force acting on the elevator.
We can set up the equation as follows:
T = ma
Now, let's rearrange the equation to solve for the acceleration (a):
a = T / m
Plugging in the values, we have:
a = 11700 N / 1200 kg
Calculating the value, we find:
a ≈ 9.75 m/s²
Therefore, the magnitude of the elevator's acceleration is approximately 9.75 m/s².
As for the motion of the elevator, based on the given information, we can determine that the elevator is accelerating upward. Since the tension force in the cable is greater than the weight of the elevator (which would be 11700 N - the force due to gravity on the elevator), the elevator is experiencing an upward net force and hence accelerating in that direction.