f(x)=x^2+3 Solve for f(2)and f(-5)

I need help, can someone please help me by explaining step by step how to solve this problem, I am most grateful to you. Thank you before hand.

just plug in the values for x and solve

f(x) = x^2 + 3
f(2) = 2^2 + 3
f(2) = ?

f(x) = x^2 + 3
f(5) = 5^2 + 3
f(5) = ?

Please forgive me, math is not my forte as you can see. Does that mean that f(5)= 5? and f(2)= 2? Thus, the answer is (5,2)or just 5 and 2? I guess what I'm trying to determing is how do you write the answer? Thank you and pleae excuse my confusion.

f(x) = x^2 + 3

f(2) = 2^2 + 3
f(2) = ?

2^2 = 4
f(2) = 2^2 + 3
f(2) = 4 + 3
f(2) = 7

the answer for f(2) is 7
when x = 2, the function value = 7

now, you do the other one

Thank you for your quick response, and your much needed help. is the answer to the the second problem 10? Thank you.

No, f(5) does not = 10

f(x) = x^2 + 3
f(5) = 5^2 + 3
f(5) = ?

5^2 = ?
5^2 + 3 = ?

show me how you got 10

I added 5 and 2 + 3. I am obviously wrong. Sorry!

I think the answer is 5 because of the polynomial 2, I could be wrong but doesn't that amount to 5 twos, in other words, 2,2,2,2,2, which equal 5, one whole number? Sorry, i'm lost.

f(x) = x^2 + 3

f(5) = 5^2 + 3
f(5) = ?

5^2 = 5 x 5 = 25
f(5) = 5^2 + 3
f(5) = 25 + 3
f(5) = 28

5^2 is "5 squared."

xxxxx
xxxxx
xxxxx
xxxxx
xxxxx
(Not a perfect square there because of the text size).

How many are in 5^2? (Just count them up. It is 5 up or 5 across in every row/column).

)

Thank you. I wholeheartedly, appreciate your help. Your help does make a big difference in how to solve some of these algebra problems. Thank you, again.