How would u figure this question out?
Does this system of linear equation have a solution of (-3,4)?
2x-3 = 6
y = 3x-13
Do u just substitute the numbers or something?
Yes, just substitute in both equations
1st:
Left Side = 2x-3 = 2(-3) - 3 = -9
but RS = 6, so the values don't even work in the first equation, you can stop here
(-3,4) is NOT a solution
I have a feeling that your first equation should have been
2x - 3y = 6
in that case:
LS - 2(-3) - 3(4) = -6
RS = +6
No point even trying the second
So no good either.
Yes, sorry Reiny I had forgotton the Y. And thanks for the explanation:)
To determine if the system of linear equations has a solution of (-3, 4), you need to substitute the values of x and y into each equation and see if both equations are satisfied simultaneously.
For the first equation, 2x - 3 = 6, we can substitute x = -3:
2(-3) - 3 = 6
-6 - 3 = 6
-9 = 6
Since -9 is not equal to 6, the first equation is not satisfied when x = -3.
For the second equation, y = 3x - 13, we can substitute x = -3 and y = 4:
4 = 3(-3) - 13
4 = -9 - 13
4 = -22
Since 4 is not equal to -22, the second equation is also not satisfied when x = -3 and y = 4.
Therefore, the system of linear equations does not have a solution of (-3, 4).