what is The total work done in lifting a typical high
school physics textbook a vertical distance of
0.10 meter
The answer is 1.5J
I'm sorry I meant 1.5J
How
But why
To find the total work done in lifting a textbook a vertical distance of 0.10 meter, you need to know the mass of the textbook and the acceleration due to gravity.
1. Determine the mass of the textbook. This information can usually be found either on the textbook itself or in its accompanying documentation.
2. Find the acceleration due to gravity. On Earth, standard gravity is approximately 9.8 meters per second squared (9.8 m/s^2). This value represents the rate at which objects accelerate towards the Earth due to its gravitational pull.
3. Use the formula for work done: Work = Force x Distance x cos(theta), where Force = mass x acceleration due to gravity.
Since the textbook is being lifted vertically, the angle (theta) between the applied force and the displacement is 0 degrees, and the cos(0) = 1. Therefore, this term simplifies to 1.
So, the equation becomes: Work = mass x acceleration due to gravity x distance.
4. Substitute the known values into the equation: Work = mass x acceleration due to gravity x distance.
For example, if the mass of the textbook is 1 kilogram, the equation becomes: Work = 1 kg x 9.8 m/s^2 x 0.10 m.
5. Calculate the work. In this case, the work done would be 0.98 Joules (1 kg x 9.8 m/s^2 x 0.10 m = 0.98 J).
Therefore, the total work done in lifting the textbook a vertical distance of 0.10 meter would be 0.98 Joules.