The function f is continuous on the closed interval [0,6] and has values that are given in the table above. The equation f(x)=3 must have at least two solutions in the interval [0,6] if k= ? A. 0 B. -1 C. 1 D. 2 E. 3
lol. and the table?
To determine the number of solutions for the equation f(x) = 3 in the interval [0,6], we need to analyze the table values of the function f(x) and find the locations where the function crosses the horizontal line y = 3.
Looking at the values in the table, we can see that the function f(x) takes a value less than 3 at x = 1, and a value greater than 3 at x = 4. This indicates that the function crosses the line y = 3 at least once in the interval [1, 4].
Therefore, we can conclude that the equation f(x) = 3 has at least one solution in the interval [0, 6]. Hence, the value of k that satisfies the condition is C. 1.