Given the following equation: Mg(s)+2HCl(aq) goes to MgCl2(s)+H2(g)
How many grams of hydrogen chloride (HCl) are needed to produce 200g of hydrogen H2?
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To find out how many grams of hydrogen chloride (HCl) are needed to produce 200 grams of hydrogen gas (H2), we can start by calculating the molar mass of HCl.
The molar mass of HCl can be calculated using the atomic masses of hydrogen (H) and chlorine (Cl) from the periodic table. The atomic mass of hydrogen is approximately 1.01 g/mol, and the atomic mass of chlorine is approximately 35.45 g/mol.
The molar mass of HCl is the sum of the atomic masses of hydrogen and chlorine:
Molar mass of HCl = Atomic mass of H + Atomic mass of Cl
= 1.01 g/mol + 35.45 g/mol
= 36.46 g/mol
From the balanced chemical equation, we know that 2 moles of HCl are required to produce 1 mole of H2. This means that the ratio of moles between HCl and H2 is 2:1.
Now, let's calculate the number of moles of H2 using the given mass (200 g) and its molar mass.
Moles of H2 = Mass of H2 / Molar mass of H2
= 200 g / (2.02 g/mol) [The molar mass of H2 is approximately 2.02 g/mol]
So, Moles of H2 = 98.51 moles
Since the ratio of moles between HCl and H2 is 2:1, we can conclude that the number of moles of HCl required will be half of the number of moles of H2.
Moles of HCl = 98.51 moles / 2
= 49.26 moles
Finally, to calculate the mass of HCl required, we can use its molar mass.
Mass of HCl = Moles of HCl x Molar mass of HCl
= 49.26 moles x 36.46 g/mol
= 1796.05 g
Therefore, approximately 1796.05 grams of hydrogen chloride (HCl) are needed to produce 200 grams of hydrogen gas (H2).