12x+20y+15z=-60
What are the directions...
recheck your problem, not enough info given
The given equation is 12x + 20y + 15z = -60. This is a linear equation in three variables (x, y, and z). To solve this equation, we need to find the values of x, y, and z that satisfy the equation.
There are multiple ways to solve this type of equation, but I will explain one method using the method of elimination.
Step 1: Choose two variables to eliminate. In this case, let's eliminate y. To do this, we need to eliminate y from two equations.
Step 2: Multiply the first equation by a suitable number such that the coefficient of y in both equations will be the same (or multiples of each other). In this case, we can multiply the first equation by 2, resulting in:
24x + 40y + 30z = -120
Step 3: Multiply the second equation by the necessary number to make the coefficient of y the same as in the first equation. In this case, the coefficient of y in the second equation is already 20, so we don't need to do anything.
Step 4: Subtract the two equations to eliminate y. In this case, the equations become:
(24x + 40y + 30z) - (12x + 20y + 15z) = -120 - (-60)
Simplifying this equation, we get:
24x + 40y + 30z - 12x - 20y - 15z = -120 + 60
Which becomes:
12x + 20y + 15z = -60
Step 5: Simplify and solve for the remaining variables. In this case, the equation we obtained in step 4 is the same as the original equation. This means that any values of x, y, and z that satisfy the original equation will also satisfy the equation we obtained in step 4.
Therefore, the solution to the original equation 12x + 20y + 15z = -60 is any set of x, y, and z that satisfy the equation.