How much heat must be added to 60 g of ice at 0 C to melt the ice completely?
6kcal
To determine the heat required to melt the ice completely, we need to use the heat equation:
q = m * ΔH
where:
q is the heat required (in joules),
m is the mass of the ice (in grams),
ΔH is the heat of fusion for ice which is 334 J/g.
Given:
m = 60 g
ΔH = 334 J/g
Let's calculate:
q = 60 g * 334 J/g
q = 20,040 J
Therefore, 20,040 joules of heat must be added to 60 grams of ice at 0°C to completely melt the ice.
To determine how much heat must be added to melt the ice completely, you need to calculate the heat required for each phase change separately. First, you'll need to calculate the heat required to raise the temperature of the ice from -273.15°C to 0°C. Then, you'll calculate the heat required to melt the ice at 0°C.
Here are the step-by-step calculations:
1. Heat required to raise the temperature of the ice:
The specific heat capacity of ice is 2.09 J/g°C.
The initial temperature is -273.15°C.
The final temperature is 0°C.
The mass of the ice is 60 g.
Heat required = mass × specific heat capacity × temperature change
= 60 g × 2.09 J/g°C × (0°C - (-273.15°C))
= 60 g × 2.09 J/g°C × 273.15°C
= 32,981.8 J
2. Heat required to melt the ice at 0°C:
The heat of fusion for ice is 334 J/g.
The mass of the ice is 60 g.
Heat required = mass × heat of fusion
= 60 g × 334 J/g
= 20,040 J
To find the total heat required to melt the ice completely, add the heat required for each phase change:
Total heat required = heat required to raise the temperature + heat required to melt the ice
= 32,981.8 J + 20,040 J
= 53,021.8 J
Therefore, approximately 53,021.8 Joules of heat must be added to 60 g of ice at 0°C to melt the ice completely.