solve for y, 5y^2-13y=6
I did forget the exponent the first time..
Gather terms on the right-hand-side, and factor:
5y^2-13y=6
5y^2-13y-6 = 0
(5y-3)(y-2)=0
y=3/5 or y=2
In google type
"quadratic equation online"
when you see list of results click on:
webgraphingcom/quadraticequation_quadraticformula.jsp
When this page be open in rectacangle type your equation,and click option solve it
You will see solution Step-by-step
No problem! Let's solve the quadratic equation for y.
The equation is:
5y^2 - 13y = 6
To solve this equation, we need to set it equal to zero. By moving the constant term to the other side, we get:
5y^2 - 13y - 6 = 0
Now, we can use factoring, completing the square, or the quadratic formula to solve for y. In this case, let's use factoring.
We need to find two numbers that multiply to give us -30 (the product of 5 and -6), and add up to -13 (the coefficient of the middle term).
The numbers that satisfy these conditions are -15 and 2.
So, we can rewrite the equation by splitting the middle term:
5y^2 - 15y + 2y - 6 = 0
Now we can factor by grouping:
(5y^2 - 15y) + (2y - 6) = 0
5y(y - 3) + 2(y - 3) = 0
Notice that we have a common binomial factor of (y - 3). We can factor that out:
(y - 3)(5y + 2) = 0
Now we can set each factor equal to zero and solve for y:
y - 3 = 0 or 5y + 2 = 0
Solving each equation, we find:
y = 3 or y = -2/5
So the solutions to the equation are y = 3 and y = -2/5.