solve for u, u=sqrt -u+6
u=�ã-u+6
do you mean
u = (sqrt(-6 + u))
please use the word 'sqrt' and put in ()
what is included under the radical
we will be able to assist you much faster if what you need is more clear
thank you
u = (sqrt(-u + 6))
u = (sqrt(6 - u))
square both sides
u^2 = 6 - u
u^2 + u - 6
complete the square
u^2 + u = 6
u^2 + u + 1/4 = 6 + 1/4
(u + 1/2)^2 = 25/4
take the square root of both sides
+ - (u + 1/2) = 5/2
u + 1/2 = 5/2
u = 4/2 = 2
-u - 1/2 = 5/2
-u = 6/2 = 3
u = -3
check for u = 2
u = (sqrt(6 - u))
2 = (sqrt(6 - 2))
2 = sqrt 4
2 = 2
check for u = -3
u = (sqrt(6 - u))
-3 = (sqrt(6 + 3))
-3 = sqrt 9
-3 not = 3
so, the only solution is u = 2
To solve for u in the equation u = √(-u + 6), follow these steps:
Step 1: Square both sides of the equation to eliminate the square root. This gives us u^2 = -u + 6.
Step 2: Rearrange the equation to move all the terms to one side. We get u^2 + u - 6 = 0.
Step 3: Factor the quadratic equation, if possible. In this case, the quadratic equation factors as (u + 3)(u - 2) = 0.
Step 4: Set each factor equal to zero and solve for u. We have two possible solutions: u + 3 = 0 or u - 2 = 0.
Solving the first equation, u + 3 = 0, we get u = -3.
Solving the second equation, u - 2 = 0, we get u = 2.
So the solutions to the equation u = √(-u + 6) are u = -3 and u = 2.