A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e., the altitude of the figure?
The altitude of the trapezoid is how many feet?
A = ((B1 + B2)/2)h = 8100F^2.
(180 / 2)h = 8100,
90h = 8100,
h = 8100 / 90 = 90Ft = Distance across
the lot.
To find the altitude of a trapezoid, you can use the formula for the area of a trapezoid and solve for the altitude.
The formula for the area of a trapezoid is A = (1/2) * (b1 + b2) * h, where A is the area, b1 and b2 are the lengths of the bases, and h is the altitude.
In this case, you are given that the sum of the bases is 180 feet, so b1 + b2 = 180. And you are also given that the area of the lot is 8,100 square feet, so A = 8,100.
Plugging these values into the formula, we get:
8,100 = (1/2) * (180) * h
Now we can solve for h. First, multiply both sides of the equation by 2 to eliminate the fraction:
16,200 = 180 * h
Next, divide both sides of the equation by 180 to isolate h:
h = 16,200 / 180
Performing the division, we get:
h = 90
Therefore, the altitude of the trapezoid, or the distance across the lot, is 90 feet.