Find the area of the following ellipse (round to nearest tenth).

a = 9 in.; b = 8 in.

a = How many sq. in.?

Forst you need to explain and underswtand what a and b are.

If a and b are the semimajor and semiminor axes, the area is
pi*a*b.

If the equation of the eclipse is
(x/a)^2 + (y/b)^2 = 1
and b are the semimajor and semiminor axes.

To find the area of an ellipse, you can use the formula: A = π * a * b, where "a" and "b" are the lengths of the semi-major and semi-minor axes of the ellipse, respectively.

In this case, the values given are a = 9 in. and b = 8 in. So, we can substitute these values into the formula to find the area.

A = π * 9 in. * 8 in.

Now, we can calculate the area using the value of π (pi). Let's assume π is approximately 3.14159.

A ≈ 3.14159 * 9 in. * 8 in.

A ≈ 226.19552 in²

To round to the nearest tenth, you would round the decimal portion to one digit after the decimal point.

So, the area of the ellipse is approximately 226.2 square inches.