Find the slope and y-intercept of the line 3x=7y+63 Thank you.
3x = 7y + 63
7y = 3x + 63
y = (3/7)x + 9
compare with y = mx + b
To find the slope and y-intercept of the line 3x = 7y + 63, we need to rewrite the equation in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
First, let's solve the equation for y:
3x = 7y + 63
Subtract 63 from both sides:
3x - 63 = 7y
Now divide both sides by 7 to isolate y:
y = (3x - 63) / 7
The equation is now in slope-intercept form. The coefficient of x, which is 3/7, represents the slope, and the constant term, which is -63/7, represents the y-intercept.
Therefore, the slope of the line is 3/7, and the y-intercept is -63/7.
To find the slope and y-intercept of a line, we need to rewrite the given equation in slope-intercept form, which has the form of y = mx + b, where m represents the slope of the line and b represents the y-intercept.
Given equation: 3x = 7y + 63
First, let's isolate y on one side of the equation by moving the 7y term to the left side. We can do this by subtracting 7y from both sides:
3x - 7y = 63
Now, let's rearrange the equation so that y is isolated and has a coefficient of 1:
-7y = -3x + 63
Divide both sides of the equation by -7:
y = (-3x + 63) / -7
Simplifying the equation further:
y = -3x/7 - 63/7
Now we have the equation in slope-intercept form. The coefficient of x, -3/7, represents the slope of the line, and the constant term, -63/7, represents the y-intercept.
Therefore, the slope of the line is -3/7 and the y-intercept is -63/7.