maths

given the following equation for a circle x^2-8x+y^2+4y+11=0 find its centre and radius

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  1. x^2-8x+y^2+4y+11=0

    by completing the square...

    x^2-8x+ 16 +y^2+4y+ 4 = -11 + 16 + 4

    (x-4)^2 + (y+2)^2 = 9

    I am sure you can take it from here

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