Choose the equations which correctly describe the dissolution of a compound into water.
a) CaBr2(s)-> Ca2+(aq) + Br2(l)
b) sodium bicarbonate(s)-> Na+(aq) + HCO3–(aq)
c) CH3OH(l)-> C4+(aq) + O2–(aq) + 4 H+(aq)
d) Ba(NO3)2(s)-> Ba2+(aq) + 2 NO3–(aq)
e) H2SO4(g)-> H+(aq) + HSO4–(aq)
f) CCl4(l)-> C4+(aq) + 4 Cl–(aq)
g) CO2(g)-> CO2(aq)
h) CaI2(s)-> CaI+(aq) + I–(aq)
i) Fe3(PO4)2(s)-> 3 Fe3+(aq) + 2 PO43–(aq)
j) perchloric acid -> H+(aq) + ClO4–(aq) k) 8 H+ +MnO4– -> Mn2+(aq) + 4 H2O(l)
l) C2H5OH + 3 H2O(l) -> 2 CO2(g) + 12 H+(aq)
m) sodium dichromate(s) -> 2 Na+(aq) + Cr2O72–(aq)
n) aluminum sulfate(s) -> Al3+(aq) + SO42–(aq)
o) SF6(g) -> S6+(aq) + 6 F–(aq)
I don't like any of them. All lack water (except for l) and that one is not balanced and the products are screwed up. Perhaps the correct one is k which you omitted.
bdegjm
bdegjm is right
BDEGJM is correct.
Recall that B is what we make slurries out of in lab.
D is an ionic compound of Ba2+ ions and No3 - anions...ionic compounds are always soluble in water of course
G works because CO2 is soluble in Water ... it usually converts into carbonic acid so that kinda threw me off.
M looks like another compound
Just from guessing, it looks like E and J work because they're both acids...which would make sense.
Just posted that in case anyone wanted to actually understand it too. Stuff like that could show up on a test.
Funny enough, people think that K was omitted XD... anywho...I'm kinda late on this, but BDEGJM is correct, but I also have this question set, I and I got this wrong for some reason. Note: the letter selections are different, but the answer selections are the same.
The equations which correctly describe the dissolution of a compound into water are:
b) sodium bicarbonate(s)-> Na+(aq) + HCO3–(aq)
d) Ba(NO3)2(s)-> Ba2+(aq) + 2 NO3–(aq)
e) H2SO4(g)-> H+(aq) + HSO4–(aq)
h) CaI2(s)-> Ca2+(aq) + 2 I–(aq)
i) Fe3(PO4)2(s)-> 3 Fe3+(aq) + 2 PO43–(aq)
j) perchloric acid -> H+(aq) + ClO4–(aq)
k) 8 H+ + MnO4– -> Mn2+(aq) + 4 H2O(l)
n) aluminum sulfate(s) -> Al3+(aq) + 3 SO42–(aq)
o) SF6(g) -> S6+(aq) + 6 F–(aq)
To determine whether an equation correctly describes the dissolution of a compound into water, you need to consider the state symbols and charges of the ions involved. In a correct equation, the compound's solid form (if it is solid) must dissolve into its respective ions in the aqueous state.
For example, in equation b) sodium bicarbonate is in its solid form (s), and it dissolves into Na+ and HCO3– ions in the aqueous state (aq).
Similarly, in equation n) aluminum sulfate is in its solid form (s), and it dissolves into Al3+ and SO42– ions in the aqueous state (aq).
Make sure to check the charges of the ions and the correct stoichiometry (ratio) between the compound and the ions in the equation to ensure accuracy.