plases help me.... im really stuck in this question... i have no clue how to do it... please help me
oxygen gas generated in the thermal decomposition of potassium chlorate in water. the total pressure of this system was measured to be 762 mmHg and the pressure of water was 22 mmHg. calculate the mass of oxygen gas when 24 degree Celsius and 0.128L of potassium chlorate was used?
2KClO₃ --> 2KCL+ 3O₂
THANK YOU!!!
I can see where you could be confused. I am confused after reading the problem, also. KClO3 is a SOLID, and it is measured in grams and not L (as in 0.128 L). Could that be grams?
Here is a worked example of KClO3 decomposition to yield oxygen gas AT any condition. But the way your problem is stated, if that is 0.128 g KClO3 and you want to know the grams oxygen, then total pressure, pressure of water, and temperature are extraneous pieces of information. Check to see exactly how your problem reads and post a clarification if necessary.
http://www.jiskha.com/science/chemistry/stoichiometry.html
ye in th question is said litres.
In which case I don't know what 0.128 L KClO3 means; therefore, I can't help. Perhaps another tutor can figure it out.
I'd be happy to help you with this question! To calculate the mass of oxygen gas generated in the thermal decomposition of potassium chlorate, we need to use the ideal gas law equation.
The ideal gas law equation is given by:
PV = nRT
Where:
P is the pressure of the gas (in atm or Pa)
V is the volume of the gas (in liters)
n is the number of moles of the gas
R is the ideal gas constant (0.0821 L·atm/mol·K or 8.314 J/mol·K)
T is the temperature of the gas in Kelvin (K)
In order to calculate the mass of oxygen gas, we need to determine the number of moles of oxygen gas produced.
First, let's convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
So, the temperature in Kelvin, T = 24 + 273.15 = 297.15 K.
Now let's calculate the number of moles of oxygen gas using the ideal gas law equation.
Rearranging the equation:
n = (PV) / (RT)
Here, we have the total pressure of the system (P = 762 mmHg = 762 / 760 atm) and the volume (V = 0.128 L). We can now substitute these values into the equation.
n = [(762 / 760) * 0.128] / [0.0821 * 297.15]