Robert says that if you toss three coins you get 3 H (3 Heads),2 H ( 2 heads), 1 H(1 Head), or oH(o Heads), so the probabliity of getting three heads is 1/4. How do you respond?
I would respond with
"Robert, you are wrong, the probability is 1/8"
Robert is wrong. The four possible outcomes are not equally likely.
The probability of getting either zero or three heads in three tosses is 1/8 (for each).
The probability of getting either one or two heads is 3/8 (for each)
What does this have to do with geometry?
your guess is as goods as mine.
I think it has more to do with probablity
The response you received from Robert regarding the probability of getting three heads when tossing three coins is incorrect. Let me explain the correct calculation for finding the probability.
To determine the probability of an event occurring, we need to divide the number of favorable outcomes by the total number of possible outcomes.
In this case, let's consider the total number of possible outcomes when tossing three coins. Each coin has two sides (heads and tails), so the total number of outcomes for one coin is 2. Since we are tossing three coins, the total number of outcomes for all three coins is 2 * 2 * 2 = 8.
Next, let's determine the number of favorable outcomes where all three coins land heads up. Since each coin has two possible outcomes and we want all three coins to land heads up, the number of favorable outcomes is 2 * 2 * 2 = 8.
Therefore, the probability of getting three heads is 8 (favorable outcomes) divided by 8 (total outcomes), which simplifies to 1.
So, the correct probability of getting three heads when tossing three coins is 1, not 1/4 as Robert stated.