How many pounds of apples costing .64 per pound must be added to 30 pounds of apples costing .49 per pound to create a mixture that would cost .58 per pround
solve ....
.64x + .49(30) = .58(x+30)
I suggest multiplying each term by 100
64x + 49(30) = 58(x+30)
easy from there ....
Thank you so much!!!(:
you have7 rotten apples in a batch of 2 apples. what percent of the apples are good
To find the number of pounds of apples needed, we need to set up an equation based on the given information.
Let's assume that the number of pounds of apples costing $0.64 per pound that needs to be added is x.
The cost of the 30 pounds of apples costing $0.49 per pound is 30 * $0.49 = $14.70.
The cost of x pounds of apples costing $0.64 per pound is x * $0.64.
The total cost of the mixture is the sum of the cost of the two batches of apples, which should equal the cost per pound of the mixture multiplied by the total weight of the mixture (30 pounds + x pounds).
Therefore, the equation becomes:
$14.70 + (x * $0.64) = ($0.58 * (30 + x))
Now, we can solve this equation to find the value of x.
14.70 + 0.64x = 0.58(30 + x)
Simplifying the equation:
14.70 + 0.64x = 17.4 + 0.58x
Subtracting 0.58x from both sides:
0.06x = 2.7
Dividing both sides by 0.06:
x = 45
Therefore, you would need to add 45 pounds of apples costing $0.64 per pound to the 30 pounds of apples costing $0.49 per pound to create a mixture that costs $0.58 per pound.