# Physics

Some how TRAIN A travelling at 36 m/s, is accidentally sidetracked onto the train track for TRAIN A. The TRAIN A engineer spots TRAIN A 100 m ahead on the same track and travelling in the same direction. The engineer jams on the brakes and slows TRAIN B at a rate of 3m/s^2. TRAIN A's conductor was unaware of the situation. If the speed of the local train is 11 m/s will the express be able to stop in time or will there be a collision?
Support you answer with a calculation.

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1. Sorry Train A is sidetracked onto Train B's train track, which is 100 m ahead of Train A

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2. v=0
u=36m/s
a=3m/s^2
t=?
v=u+at
0=36m/s-3m/s^2t
0=-36=3t
t=36/2
=18 seconds.

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3. the answer is 12 seconds. you divide 36 by 3 not 2.

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