Math

if log(x+1) 27=3 find the value of x

*(x+1) is the base

i know that the answer is 2 but i have no clue how to get that

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  1. log(x+1) 27=3

    since,
    logb N = x
    b^x = N

    this can be written as
    (x + 1)^3 = 27
    take cube root of each side
    x + 1 = 3
    x = 2

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