How many grams of oxygen gas are reacted if 75 g of hydrogen gas is consumed?

Start from the equation for the reaction

O2 + 2H2 -> 2H2O

so 1 mole of O2 reacts with 2 moles of H2.

75 g of H2 gas contains

75 g/2 g mole^-1 = 37.5 mole

this will react with 37.5 mole/2 moles of O2 (from the equation)

hence calculate the number of grams of O2 gas (molar mass = 32 g mole^-1)

To determine the number of grams of oxygen gas reacted, we need to know the balanced chemical equation for the reaction between hydrogen gas (H2) and oxygen gas (O2).

The balanced equation for this reaction is:

2 H2 + O2 → 2 H2O

From the equation, we can see that 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water.

To find the number of grams of oxygen gas, we'll follow these steps:

Step 1: Convert the given mass of hydrogen gas to moles.
To do this, we need to know the molar mass of hydrogen gas (H2), which is 2 g/mol.

Given mass of hydrogen gas = 75 g
Molar mass of hydrogen gas (H2) = 2 g/mol

(Number of moles of H2) = (Given mass of H2) / (Molar mass of H2)
(Number of moles of H2) = 75 g / 2 g/mol
(Number of moles of H2) = 37.5 mol

Step 2: Use the balanced equation to determine the ratio of moles between H2 and O2.
From the balanced equation: 2 moles of H2 react with 1 mole of O2.

Using the ratio, we can calculate the number of moles of oxygen gas:

(Number of moles of O2) = (Number of moles of H2) / 2
(Number of moles of O2) = 37.5 mol / 2
(Number of moles of O2) = 18.75 mol

Step 3: Convert the moles of oxygen gas to grams.
To do this, we need to know the molar mass of oxygen gas (O2), which is 32 g/mol.

Given number of moles of O2 = 18.75 mol
Molar mass of oxygen gas (O2) = 32 g/mol

(Number of grams of O2) = (Given number of moles of O2) * (Molar mass of O2)
(Number of grams of O2) = 18.75 mol * 32 g/mol
(Number of grams of O2) = 600 g

Therefore, if 75 g of hydrogen gas is consumed, approximately 600 grams of oxygen gas would be reacted.