HOW DO YOU BALANCE THE FOLLOWIN CHEMICAL REACTIO???

When,heated solid iron reacts with solution of copper(II)sulfate to yield aqueous iron(II)sulfate and solid copper metal?

Fe(s) + CuSO4(aq) ==> FeSO4(aq) + Cu(s)

balanced as is.

To balance the chemical equation, you need to ensure that the number of atoms of each element is equal on both sides of the reaction. In this case, we have the following unbalanced equation:

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

Let's balance the equation step by step:

Step 1: Balance the metals
In this reaction, we have one iron atom on the left side and one copper atom on the right side. Therefore, the balanced equation becomes:

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

Step 2: Balance the non-metals
Next, we balance the non-metal atoms, namely sulfur and oxygen, within the sulfate ions:

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

Step 3: Check and balance the charges
Lastly, we check the charges of the ions involved. In this equation, everything is neutral, so no adjustments are necessary.

The final balanced equation is:

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)