State the solutions, or estimated solutions, to each quadratick equation. We have

equation is x^2-9x+20.25=0 and the graph is y=x^2-9x+20.25

Not sure how to figure this one out. I assume I just solve the equation and not the graph to get the ordered pairs?

If you use the Quadratic Formula, you

will notice that the value under the radical = 0:

B^2 = 4AC = 81,
B^2 - 4AC = 0,
Therefore, X = -B / 2A = 9 / 2 = 4.5.

To find the solutions, or estimated solutions, to the quadratic equation x^2-9x+20.25=0, you can use the quadratic formula:

x = (-b ± √(b^2-4ac)) / (2a)

Given that the equation is in the form of ax^2 + bx + c = 0, the coefficients for this equation are:
a = 1 (coefficient of x^2)
b = -9 (coefficient of x)
c = 20.25

Substituting these values into the quadratic formula, we get:

x = (-(-9) ± √((-9)^2 - 4(1)(20.25))) / (2(1))

Simplifying further:

x = (9 ± √(81 - 81)) / 2

x = (9 ± √0) / 2

Since the discriminant (the value inside the square root) is zero, this means that the quadratic equation has only one distinct solution.

Therefore, the solution to the equation x^2 - 9x + 20.25 = 0 is:

x = 9/2

So, the ordered pair representing the solution would be (9/2, 0) on the graph y = x^2 - 9x + 20.25.