Physics

A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 5.00 cm. What is the oscillation frequency of the two block system?

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asked by Tara
  1. F=kx = mg

    x=mg/k
    but for the second block we have

    x+.05=2mg/k

    setting the x equal..

    mg/k-2mg/k=-.05
    -mg/k=-.05
    k= mg/.05

    now frequency:

    f= 1/2pi sqrt (k/m)

    put that k int the expression, and you have the answer.

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