A bobsled slides down an ice track starting

(at zero initial speed) from the top of a(n)
146 m high hill.
The acceleration of gravity is 9.8 m/s2 .
Neglect friction and air resistance and de-
termine the bobsled’s speed at the bottom of
the hill.
Answer in units of m/s.

The change in Kinetic Energy has to be equal to the change in Potentialenergy.

1/2 mv^2=mg*146

v^2=2g(146)

To find the speed of the bobsled at the bottom of the hill, we can use the principle of conservation of energy.

The total mechanical energy of the bobsled is conserved, so the potential energy at the top of the hill is converted to kinetic energy at the bottom.

The potential energy of the bobsled at the top of the hill is given by:

PE = mgh

Where m is the mass of the bobsled, g is the acceleration due to gravity, and h is the height of the hill.

The kinetic energy of the bobsled at the bottom of the hill is given by:

KE = (1/2)mv^2

Where v is the speed of the bobsled at the bottom of the hill.

Since the total mechanical energy is conserved, we can equate the potential energy at the top to the kinetic energy at the bottom:

mgh = (1/2)mv^2

We can cancel the mass m from both sides of the equation:

gh = (1/2)v^2

Now we can solve for v:

v^2 = 2gh

v = √(2gh)

v = √(2 * 9.8 m/s^2 * 146 m)

v ≈ 42.8 m/s

Therefore, the bobsled's speed at the bottom of the hill is approximately 42.8 m/s.

To determine the bobsled's speed at the bottom of the hill, we can use the principles of motion and gravitational acceleration.

First, we need to determine the time it takes for the bobsled to slide down the hill. We can use the kinematic equation:

h = (1/2) * g * t^2,

where h is the height of the hill, g is the acceleration due to gravity, and t is the time.

Rearranging the equation to solve for t, we have:

t = sqrt((2 * h) / g),

Substituting the given values, we get:

t = sqrt((2 * 146) / 9.8) = sqrt(29.8) ≈ 5.46 seconds.

Now that we have the time it takes for the bobsled to reach the bottom of the hill, we can use another kinematic equation:

v = g * t,

where v is the final velocity or speed of the bobsled.

Substituting the values, we have:

v = 9.8 * 5.46 ≈ 53.51 m/s.

Therefore, the speed of the bobsled at the bottom of the hill is approximately 53.51 m/s.