The Great Pyramid of Cheops has a square base of 771 ft. on a side and a height of 486 Ft. how many rooms on a side and a height of 486 ft. How many rooms 35 ftx 20ftx8ft would be needed to have a volume equivalent to that of the Great Pyramid?

(1/3) h * 771^2/vr = (1/3)(486)(594,441)/35*20*8

=

i don't understand your reasoning

To determine the number of rooms needed to have a volume equivalent to that of the Great Pyramid of Cheops, we first need to calculate the volume of the pyramid and the volume of each room. Then we can divide the total volume of the pyramid by the volume of each room to find the number of rooms needed.

Step 1: Calculate the volume of the Great Pyramid of Cheops
The formula for the volume of a pyramid is V = (1/3) * base area * height. In this case, the base area is the area of a square, calculated as side^2.

V_pyramid = (1/3) * side^2 * height
V_pyramid = (1/3) * 771 ft * 771 ft * 486 ft

Step 2: Calculate the volume of each room
The volume of each room is given as 35 ft x 20 ft x 8 ft.

V_room = length * width * height
V_room = 35 ft * 20 ft * 8 ft

Step 3: Calculate the number of rooms needed
To find the number of rooms needed, we divide the volume of the pyramid by the volume of each room.

Number of rooms = V_pyramid / V_room

Now, let's go ahead and calculate the results.

V_pyramid = (1/3) * 771 ft * 771 ft * 486 ft
V_pyramid ≈ 91,764,102 ft^3

V_room = 35 ft * 20 ft * 8 ft
V_room = 5,600 ft^3

Number of rooms ≈ V_pyramid / V_room
Number of rooms ≈ 91,764,102 ft^3 / 5,600 ft^3

Therefore, you would need approximately 16,355 rooms (rounded to the nearest whole number) of dimensions 35 ft x 20 ft x 8 ft in order to have a volume equivalent to that of the Great Pyramid of Cheops.