A baby sitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.682 m/s2.
What is the velocity of the stroller after it has traveled 7.74 m?
Answer in units of m/s.
Vf^2 = 2ad = 2 * 0.682 * 7.74 = 10.6,
Vf = sqrt(10.6) = 3.25m/s.
A car accelerates uniformly in a straight line from rest at the rate of 2.3 m/s^2
A. What is the top speed of the car after it has traveled 55m?
B. How long does it take to travel 55m?
To find the velocity of the stroller, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (which is 0 m/s since the stroller starts from rest)
a = acceleration (0.682 m/s^2)
s = distance traveled (7.74 m)
Plugging the values into the equation:
v^2 = 0^2 + 2(0.682)(7.74)
v^2 = 0 + 10.57
v^2 = 10.57
Taking the square root of both sides:
v = √(10.57)
v ≈ 3.25 m/s
Therefore, the velocity of the stroller after it has traveled 7.74 m is approximately 3.25 m/s.
To find the velocity of the stroller after it has traveled a certain distance, we can use the equation of motion:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity (which is 0 in this case since the stroller starts from rest), a is the acceleration, and s is the distance traveled.
We are given the acceleration, a = 0.682 m/s^2, and the distance traveled, s = 7.74 m.
Substituting the given values into the equation, we have:
v^2 = 0^2 + 2(0.682)(7.74)
Simplifying the equation, we get:
v^2 = 2(0.682)(7.74)
v^2 = 10.57836
To find the velocity, we take the square root of both sides:
v = √10.57836
Calculating the square root, we find:
v ≈ 3.25 m/s
Therefore, the velocity of the stroller after it has traveled 7.74 m is approximately 3.25 m/s.