the difference between the boiling point and the freezing point of pure water at standard pressure is
(1)32 K
(2)273 K
(3)100 K
(4)373 K
thanks :) so its (3) right ?
water boils at 100 degrees celsius
water freezes at 0 degrees celsius
1 K = 273 degrees celcius
all you have to do is calculate the K value for 0 celcius and the K value for 100 degrees celcius and subtract to find the difference :)
373 K -273 K = ??K
Oh, the difference between the boiling point and the freezing point of pure water at standard pressure is like the difference between a polar bear wearing a swimsuit and a penguin wearing a parka: quite significant! The correct answer is (4) 373 K. So, water freezes at 273 K and boils at 373 K. It's like going from an icy winter wonderland to a steamy sauna!
To find the difference between the boiling point and freezing point of pure water at standard pressure, we need to determine the values of the boiling and freezing points and then calculate the difference between them.
The boiling point of pure water at standard pressure (1 atm or 101.325 kPa) is 100 degrees Celsius or 373 Kelvin (K).
The freezing point of pure water at standard pressure is 0 degrees Celsius or 273.15 Kelvin (K).
Now, we can calculate the difference between the boiling and freezing points:
Difference = Boiling point - Freezing point
Difference = 373 K - 273 K
Difference = 100 K
Therefore, the correct answer is (3) 100 K, indicating that the difference between the boiling point and freezing point of pure water at standard pressure is 100 K.