A cat chases a mouse across a 1.7 m high

table. The mouse steps out of the way, and
the cat slides off the table and strikes the floor
2.1 m from the edge of the table.
The acceleration of gravity is 9.81 m/s2 .
What was the cat’s speed when it slid off
the table?
Answer in units of m/s.

The time to fall H = 1.7 m, when there is zero initial vertical velocity component, is

t = sqrt(2H/g) = 0.589 s

The cat's speed when sliding off is
Vx = 2.1 m/0.589 s = 3.57 m/s,

since the cat's horizontal velocity component, Vx, remains constant during the fall.

A cat chases a mouse across a 1.7 m high

table. The mouse steps out of the way, and
the cat slides off the table and strikes the floor
2.8 m from the edge of the table.
The acceleration of gravity is 9.81 m/s
2
.
What was the cat’s speed when it slid off
the table?
Answer in units of m/s.

Well, I don't know about you, but this seems like a classic case of a failed acrobatic act by the cat! Anyway, let's do some calculations to find out the cat's speed when it slid off the table.

First, we need to find the time it took for the cat to fall from the table to the floor. We can use the equation:

h = (1/2) * g * t^2

Where h is the height of the table (1.7 m), g is the acceleration due to gravity (9.81 m/s^2), and t is the time.

By rearranging the equation, we can solve for t:

t = sqrt((2 * h) / g)

Plugging in the values, we get:

t = sqrt((2 * 1.7) / 9.81) = 0.579 s (rounded to 3 decimal places)

Now that we have the time, we can find the cat's horizontal speed using the equation:

distance = speed * time

The distance the cat traveled horizontally is given as 2.1 m, and the time is 0.579 s. Solving for speed:

2.1 = speed * 0.579

speed = 2.1 / 0.579 ≈ 3.63 m/s (rounded to 2 decimal places)

So, the cat's speed when it slid off the table is approximately 3.63 m/s. I hope the cat learned its lesson about chasing mice on tables!

To find the cat's speed when it slid off the table, we can use the principles of projectile motion. Let's break down the information given:

Initial vertical displacement (h) = 1.7 m
Horizontal distance traveled (x) = 2.1 m
Acceleration due to gravity (g) = 9.81 m/s^2

Since the motion of the cat off the table involves both horizontal and vertical components, we need to analyze them separately.

First, let's calculate the time it takes for the cat to fall from the table by using the vertical motion equation:

h = (1/2) * g * t^2

Rearranging the equation to solve for time (t):

t = sqrt(2h / g)

t = sqrt(2 * 1.7 / 9.81) ≈ 0.588 seconds

Now that we have the time it takes for the cat to fall, we can calculate the horizontal velocity (speed) using the equation:

x = v * t

Rearranging the equation to solve for velocity (v):

v = x / t

v = 2.1 / 0.588 ≈ 3.57 m/s

Therefore, the cat's speed when it slid off the table was approximately 3.57 m/s.

guys its literally 0.978 m/s duh

sdfsdfsdf