s=1/2(a-b)x find b
s=1/2(a-b)x
s = 1/2(xa) - 1/2(xb)
s - 1/2(xa) = - 1/2(xb)
multiply both sides by -2
-2s + xa = xb
divide both sides by x
(-2s + xa)/x = b
not a tutor, re-check
To find the value of b in the equation s = 1/2(a - b)x, we can rearrange the equation to isolate b.
s = 1/2(a - b)x
First, multiply both sides of the equation by 2 to eliminate the fraction:
2s = (a - b)x
Next, divide both sides of the equation by x to solve for a - b:
(2s) / x = a - b
To find b, we want to isolate it on one side of the equation. To do this, we can subtract (2s) / x from both sides:
(2s) / x - (2s) / x = a - b - (2s) / x
0 = a - b - (2s) / x
Now, let's rearrange the equation to solve for b:
b = a - (2s) / x
Therefore, the value of b in terms of a, s, and x is b = a - (2s) / x.