Where do I look for the domain in this-
The domain of y =1/(x-6) + 3
Possible answers:
All real numbers except x=6
All real numbers except x = -6
All real numbers except x=3
All real numbers except x= -3
Thank you
the function is undefined when x = 6 because of the zero denominator
so the answer is x = 6 according to what you're saying? and the domain is the (h) in here correct? So in the future I just look for the h , take the opposite and that is my domain?
To determine the domain of the given function, y = 1/(x-6) + 3, we need to identify any values that would make the function undefined.
In this case, there is only one potential issue: the denominator (x-6) should not equal zero. Therefore, we need to find the value of x that makes (x-6) equal to zero.
Setting x-6 equal to zero and solving for x, we have:
x - 6 = 0
x = 6
So, x = 6 would make the function undefined.
Therefore, the domain of the function is all real numbers except x = 6.
Hence, the correct answer is: All real numbers except x = 6.