If you toss a pair of dice 1,000 times, how many times would you expect to get a sum of 12 as the result?
1.)about 12 times
2.)about 27 times
3.)about 36 times
4.)about 100 times
The lesson doesn't show me how to work this. Whats the formula?
the prob of getting 12 when tossing 2 dice = 1/36
so the number expected doing this 1000 times
= 1000 x 1/36 = 250/9
= 27.777
so it would happen approx 28 times.
If you toss 3 coins 10,000 times, how many times would you expect that exactly 2 heads appear?
Tossing a die= 1/36 and so, the number expected of doing this 1000= 1/36 *1000=27.77777778 Approximately 28
36
To determine the number of times you would expect to get a sum of 12 when tossing a pair of dice 1,000 times, we need to calculate the probability of getting a sum of 12 on a single toss, and then multiply it by the total number of tosses.
The formula for the probability of getting a sum of 12 is:
P(sum of 12) = Number of ways to get a sum of 12 / Total number of possible outcomes
Next, let's find the number of ways to get a sum of 12 when rolling a pair of dice. When rolling two dice, the maximum possible sum that can be obtained is 12, and there are two ways to achieve this: (6, 6) and (5, 7) (or vice versa).
Thus, the number of ways to get a sum of 12 is 2.
The total number of possible outcomes when rolling two dice is:
Total outcomes = Number of outcomes on the first die * Number of outcomes on the second die
Since each die has 6 possible outcomes, the total number of possible outcomes is:
Total outcomes = 6 * 6 = 36
Now, we can calculate the probability of getting a sum of 12:
P(sum of 12) = 2 / 36 = 1 / 18
To find the number of times you would expect to get a sum of 12 out of 1,000 tosses, multiply the probability by the total number of tosses:
Expected times = Probability * Number of tosses
Expected times = (1 / 18) * 1,000 = 55.56 (rounded to the nearest whole number)
Given the available answer choices, the closest option is 3.) about 36 times.