draw one set of letter from set 1 and place in set 2 draw one letter from set 2 place in set 3 now draw one letter from set 3 what is the probability that the last letter drawn is b? set 1 = bcb set 2 = bb set 3 = b
To find the probability that the last letter drawn is "b," we can follow these steps:
Step 1: Determine the total number of possible outcomes
In Set 1, we have three letters: b, c, and b. In Set 2, we have two letters: b and b. In Set 3, we only have one letter: b.
So, the total number of possible outcomes is 3 (from Set 1) x 2 (from Set 2) x 1 (from Set 3) = 6.
Step 2: Determine the number of favorable outcomes
Since we want the last letter drawn to be "b," we need the first two letters drawn not to be "b." Therefore, in Set 1, we have two non-"b" letters: c and b. In Set 2, we have one non-"b" letter: b. In Set 3, we have no other option except "b."
So, the number of favorable outcomes is 2 (from Set 1) x 1 (from Set 2) x 1 (from Set 3) = 2.
Step 3: Calculate the probability
The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
Probability = number of favorable outcomes / total number of possible outcomes
In this case, the probability is 2/6, which simplifies to 1/3 or approximately 0.333. Therefore, the probability that the last letter drawn is "b" is 1/3 or 0.333.