CaCl2(s) Ca2+(aq) + 2 Cl-(aq)
H = -81.5 kJ
A 14.0 g sample of CaCl2 is dissolved in 130. g of water, with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat lost to the surroundings and assuming the solution has a specific heat capacity of 4.18 J/°C·g.
I need a step by step process on how to do this.

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  1. Note the reaction produces 81.5 kJ energy per 1 mol CaCL2.
    Convert that to kJ/1 g CaCl2.
    q = mass x speific heat water x (Tf-Ti).
    mass = 14.0
    sp.h. water is in the problem.
    Tf is final T
    Ti is initial T.

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