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(( distance between two points ))

show that A(4,2), B(-2,-2) and C(2,-8)are the vertices of an isoceles right triangle.

please in detales .. thank u

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  1. The lengths of the sides are
    AB: sqrt(6^2 + 4^2) = sqrt 52 (side c)
    BC: sqrt (4^2 + 6^2) = sqrt 52 (side a)
    AC: sqrt (2^2 + 10^2) = sqrt 104 (side b)
    This proves that two sides are equal and that it is a right triangle since
    c^2 + a^2 = b^2.

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