A piece of metallic iron (10 moles) was dissolved in concentrated hydrochloric acid. The reaction formed hydrogen gas and iron chloride. How many moles of iron (II) chloride were formed? Don't forget the units.
8.5
To find the number of moles of iron (II) chloride formed, we need to first balance the chemical equation for the reaction between metallic iron and hydrochloric acid. The balanced equation is:
Fe + 2HCl -> FeCl2 + H2
From the balanced equation, we can see that 1 mole of iron reacts with 2 moles of hydrochloric acid to produce 1 mole of iron (II) chloride and 1 mole of hydrogen gas.
Given that you have 10 moles of metallic iron, we can use this information to calculate the number of moles of iron (II) chloride formed.
Since 1 mole of iron reacts with 1 mole of iron (II) chloride, we can conclude that the number of moles of iron (II) chloride formed will be the same as the number of moles of iron used, which is 10 moles.
Therefore, the number of moles of iron (II) chloride formed is 10 moles.