A polot flies 630 miles wit a tail wind of 35 miles per hour. Against the wind, he flies only 455 miles in the same amount of time. Find the rate of the plane in still air.
630=(r+35)time
455=(r-35)time
Divide the second equation into the first...
630/455= (r+35)/(r-35)
solve for r.
Thanks once again.. bobpursley
I am still not coming up with the correct answer can you show me how to work it out??? Help
train A and B are traveling in the same direction on a parallel tracks. Train A is traveling at 40 miles per hour and Train B is traveling at 48 miles per hour. Train A passes a station at 3:15pm. If train B passes the same station at 3:45pm. At what time will train B catch up with train A
To find the rate of the plane in still air, we can use the formula:
Rate of the plane in still air = (Distance with the wind - Distance against the wind) / 2
Given that the distance with the wind is 630 miles and the distance against the wind is 455 miles, we can substitute these values into the formula:
Rate of the plane in still air = (630 - 455) / 2
Rate of the plane in still air = 175 / 2
Rate of the plane in still air = 87.5 miles per hour
Therefore, the rate of the plane in still air is 87.5 miles per hour.