At 1285°C, the equilibrium constant for the reaction

Br2 (gas) <---> 2Br (gas) is Keq= 1.04 X 10^ -3

A 0.200-L vessel containing an equilibrium mixture of gases has 0.245 g. Br2 (gas) in it. What is the mass of Br (gas) in the vessel? What are the concentrations of Br2 and Br?

asked by Mina
  1. 0.245 g Br2. 0.245g/159.808 = 0.00153 moles Br2. M = 0.00153 moles/0.200 L = 0.00767 M.
    Br2(g) ==> 2Br(g)

    Keq = (Br)^2/(Br2) = 1.04E-3
    You know (Br2) and you know Keq, solve for (Br) which will be in moles/L. To find g Br, convert (Br) in mols/L to moles in 0.200 L, then to grams (g = moles x molar mass). Post your work if you get stuck.

    posted by DrBob222
  2. I'm having some difficulty getting the answer...I completely follow your logic and your numbers make sense, but I end up getting 1.129 as my final answer while the back of the book says it should be 0.00767....

    posted by Marina

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