0.245 g Br2. 0.245g/159.808 = 0.00153 moles Br2. M = 0.00153 moles/0.200 L = 0.00767 M.
Br2(g) ==> 2Br(g)
Keq = (Br)^2/(Br2) = 1.04E-3
You know (Br2) and you know Keq, solve for (Br) which will be in moles/L. To find g Br, convert (Br) in mols/L to moles in 0.200 L, then to grams (g = moles x molar mass). Post your work if you get stuck.
I'm having some difficulty getting the answer...I completely follow your logic and your numbers make sense, but I end up getting 1.129 as my final answer while the back of the book says it should be 0.00767....
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