Determine the mass of phosphoric acid that can be produced by the reaction of 1 ton of phosphate rock, Ca(PO4)2, and sulfuric acid.

To determine the mass of phosphoric acid that can be produced, you need to first calculate the amount of moles of the limiting reactant, which in this case is phosphate rock (Ca(PO4)2), and then convert it to mass using its molar mass.

1. Start by writing the balanced equation for the reaction:
Ca(PO4)2 + 3H2SO4 → 2H3PO4 + CaSO4

2. Determine the molar mass of Ca(PO4)2:
The molar mass of Ca(PO4)2 can be calculated by summing the molar masses of its constituent elements:
Molar mass of Ca = 40.08 g/mol
Molar mass of P = 30.97 g/mol
Molar mass of O (3 atoms) = 3 * 16.00 g/mol

Therefore, the molar mass of Ca(PO4)2 is:
Molar mass of Ca(PO4)2 = (40.08 g/mol) + (2 * 30.97 g/mol) + (4 * 16.00 g/mol)

3. Convert the mass of 1 ton of Ca(PO4)2 to grams:
1 ton = 1000 kg = 1000000 g

4. Calculate the moles of Ca(PO4)2 using its molar mass:
Moles of Ca(PO4)2 = (Mass of Ca(PO4)2 in grams) / (Molar mass of Ca(PO4)2)

5. According to the balanced equation, 1 mole of Ca(PO4)2 reacts to form 2 moles of H3PO4. Therefore, multiply the moles of Ca(PO4)2 by the stoichiometric coefficient of H3PO4 (2) to find the moles of H3PO4 that can be produced.

6. Finally, convert the moles of H3PO4 to mass using its molar mass:
Molar mass of H3PO4 = (3 * 1.01 g/mol) + (1 * 31.00 g/mol) + (4 * 16.00 g/mol)

By following these steps, you can calculate the mass of phosphoric acid that can be produced.