# Physics

If a car drives off a 40 m high cliff with a horizontal velocity of 15 m/s, how far from the base of the cliff will the car strike the fround? Could someone help with the equation, please

1. 0
2. 2
1. How long does it take to fall 40 m?

h= 1/2 g t^2
solve for t.

Now, given that time in the air, how far did the car travel horizontally?
distance= 15*t

posted by bobpursley
2. So I say:
40 m = 1/2 (9.8) * t^2
40/4.9 = 8.16(t^2)
sqrt of 8.16 = 2.86 = time
15 * 2.86 = 42.9 for how far from the base of the cliff the car stuck the ground

Is this correct?
Thank you for helping-
I'm homeschooled and trying to learn Physics on my own

posted by JessieLynne

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