Sam dropped a stone from her bedroom window.How high is the window if the stone travels for 2 seconds?
d = Vi*t + (1/2)a*t^2
Because the stone is dropped, initial velocity is 0.
Acceleration is due to gravity, g=9.81m/s/s.
d = (1/2)g*2^2
d=?
19.6
To determine the height of the window from which the stone was dropped, we can use the formula for free fall motion:
h = (1/2) * g * t^2
Where:
h = height
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
In this case, the time is given as 2 seconds. Plugging in the values:
h = (1/2) * 9.8 * (2^2)
= (1/2) * 9.8 * 4
= 19.6 meters
Therefore, the height of the window from which Sam dropped the stone is approximately 19.6 meters.