find slope 2x-20y+18=0
I've been braking my head and I just can't find the solution. Can you please help me. I would really appreciate your help. Thank you so very much. I now it's m= something, but I don't know what the answer is. Thanks, again!
see above
the answer is 1/10.
A linear equation is set up like this:
ax+by=c
where a,b are NOT EQUAL to 0. x and y represents coordinates.
anyhow,
to find the slope in this equation i did the following steps.
1. i made the equation into a correct linear equation so..
2x-20y+18=0
-18 -18
----------------
2x-20y=-18
2. to find the slope its m=-a/b.
so....
2x-20y=-18
ax+by=c --> m=-a/b
m=-2/-20
simplified --> m=1/10
Of course! To find the slope of the line 2x-20y+18=0, you can rewrite the equation in slope-intercept form (y = mx + b), where m represents the slope.
In order to rewrite the equation, let's isolate the term with y by moving the other terms to the other side of the equation:
2x - 20y + 18 = 0
-20y = -2x - 18
Divide both sides of the equation by -20:
y = (2/20)x + (18/20)
Simplify the fractions:
y = (1/10)x + (9/10)
Now we can see that the equation is in the form y = mx + b, where m is the slope. The coefficient of x, which is (1/10), represents the slope.
Therefore, the slope of the line 2x-20y+18=0 is 1/10.