which one of these is a possible reaction?
Cl2 + Br2
Br^-1 + I^-1
I2 + Cl^-1
Br2 + I^-1
To determine which reaction is possible, we need to look at the reactivity of the elements and their respective charges.
In general, the reactivity pattern of halogens follows this trend: Fluorine > Chlorine > Bromine > Iodine. This means that chlorine can displace bromine and iodine, bromine can displace iodine, but iodine cannot displace any of the other halogens.
Let's analyze each given reaction:
1. Cl2 + Br2:
In this reaction, chlorine (Cl2) is trying to react with bromine (Br2). According to the reactivity pattern, chlorine is more reactive than bromine, so this reaction is possible. The chlorine will displace the bromine, leading to the formation of Cl2 and Br^-1.
2. Br^-1 + I^-1:
This reaction involves bromide (Br^-1) and iodide (I^-1) ions. Both bromide and iodide have negative charges, which means they cannot displace each other. Thus, this reaction is not possible.
3. I2 + Cl^-1:
Here, iodine (I2) is attempting to react with chloride (Cl^-1). As mentioned earlier, iodine is less reactive than chlorine. Therefore, this reaction is not possible.
4. Br2 + I^-1:
This reaction consists of bromine (Br2) reacting with iodide (I^-1). Since bromine is more reactive than iodine, this reaction is possible. The bromine will displace the iodide, resulting in the formation of Br2 and I^-1.
So, the possible reaction among the given options is Cl2 + Br2.
The possible reaction among the given options is:
Br2 + I-1 → 2I-1 + Br2