At 100 degrees celsius, the ratio of the average kinetic energy of oxygen molecules, O2, to the average kinetic energy of methane molecules, CH4, is:

A) 4:1
B) 1:4
C) 1:2
D) 1:1

I think it's D because the kelvin temperature is the same for both collection of gases, and under the Kinetic Molecular Theory, the avg. KE of a gas is directly proportional to its kelvin temperature. Is that right?

Yes, you are correct in your understanding of the Kinetic Molecular Theory. According to the theory, the average kinetic energy of a gas molecule is directly proportional to its Kelvin temperature. Therefore, if the Kelvin temperature is the same for both collections of gases, then the ratio of their average kinetic energies will also be 1:1.

However, it is important to note that in this specific question, the given temperature is 100 degrees Celsius. To apply the Kinetic Molecular Theory, you need to convert this temperature to Kelvin. The conversion from Celsius to Kelvin is done by adding 273.15 to the Celsius temperature. So, 100 degrees Celsius is equal to 100 + 273.15 = 373.15 Kelvin.

Now that you have the temperature in Kelvin for both oxygen (O2) and methane (CH4), you can conclude that the ratio of their average kinetic energies is 1:1, as you mentioned. Therefore, the correct answer to the question is D) 1:1.

Your reasoning is correct! According to the Kinetic Molecular Theory, the average kinetic energy of a gas is directly proportional to its Kelvin temperature. Since both oxygen (O2) and methane (CH4) are at the same temperature, their average kinetic energies will be the same. Therefore, the ratio of their average kinetic energies is 1:1. So, the correct answer is D) 1:1.