tan 30degrees = sin 60degrees /1+cos 60degrees
I pluged in the numebrs and i got this .
�ã3/3= �ã3/2 / 1+1/2
now i don't know how to work the problem to get the answer which is supposed to be �ã3/3=�ã3/3
i want an explaintion cuz i want to know how to do it.. and let me know if i pluged them wrong.
ã is the square root sign i don't know why it changed .
in the denominator, you have 1 1/2 which is 3/2
okay still i end up with this
square root of 3/3 =square root of 3/2 / 3/2
??
The right side
= (√3/2) / (1 + 1/2)
= √3/(2) / (3/2)
= (√3/2)(2/3_
= √3/2
= left side
tan30 = sin60 / (1 + cos60).
sqrt(3)/3 = sqrt(3)/2 / (1 + 1/2),
sqrt(3)/3 = sqrt(3)/2 / (3/2),
sqrt(3)/3=sqrt(3)/2 * 2/3, The 2 cancel
sqrt(3)/3 = sqrt(3)/3.
To solve the equation tan 30 degrees = sin 60 degrees / (1 + cos 60 degrees), let's break it down step by step.
First, let's verify if the numbers you plugged in are correct. The values for sin 60 degrees = √3/2 and cos 60 degrees = 1/2 are correct. Therefore, we can proceed with the calculation.
The equation becomes:
tan 30 degrees = (√3/2) / (1 + 1/2)
Now, simplify the equation further:
tan 30 degrees = (√3/2) / (3/2)
Next, divide the numerator and denominator by 2:
tan 30 degrees = (√3/2) * (2/3)
The 2 in the numerator cancels out with the 2 in the denominator:
tan 30 degrees = √3/3
So, your calculation was correct, and the answer is indeed √3/3.