A 5.4 kg wagon is pulled along a horizontal surface. The acceleration of the object is 0.9 m/s^2. What is the coefficient of friction between the surfaces?

Any help is much appreciated! I am not sure how to go about the problem other than I think I must use the Fn (normal force) = Fg (weight) = m(mass) x g (gravitat. field strength).

I forgot to mention that the wagon is pulled by a force of 20 N.

Sliding Coefficient of Friction:

http://www.roymech.co.uk/Useful_Tables/Tribology/co_of_frict.htm

Fnet=Fapp-Friction force
ma=20N-(mu)*(N)
since normal force= weight
ma=20N-(mu)*(mg)

solve for mu.

To find the coefficient of friction between the surfaces, let's break down the problem step by step. Here's how you can solve it:

1. Identify the given information:
- Mass of the wagon (m) = 5.4 kg
- Acceleration of the object (a) = 0.9 m/s^2
- Gravitational field strength (g) = 9.8 m/s^2 (standard value on Earth)

2. Calculate the force applied to the wagon:
The force applied to the wagon is given by Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
F = 5.4 kg * 0.9 m/s^2
F = 4.86 N

3. Calculate the weight of the wagon:
The weight of the wagon is the force exerted on it due to gravity. On Earth, the weight (Fg) is given by the formula:
Fg = m * g
Fg = 5.4 kg * 9.8 m/s^2
Fg = 52.92 N

4. Determine the normal force:
The normal force (Fn) is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the weight of the wagon since it is on a horizontal surface:
Fn = Fg
Fn = 52.92 N

5. Find the frictional force:
The frictional force (Ff) can be calculated using the equation Ff = µ * Fn, where µ is the coefficient of friction. Since we need to find the coefficient of friction, we rearrange the equation:
µ = Ff / Fn

6. Substitute the given force applied to the wagon into the equation:
µ = Ff / Fn
µ = 4.86 N / 52.92 N
µ = 0.0919

Therefore, the coefficient of friction between the surfaces is approximately 0.0919.