A human has a reasonable chance of surviving an automobile crash is the body's deceleration is no more than 30 "g's". (1 "g" is 9.8 m/s^2) Calculate the force the body would have withstand decelerating at this rate. What is the distance travelled if the car was initially travelling at 90 km/hr?

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To calculate the force the body would have to withstand during deceleration, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration is the deceleration experienced, which is given as 30 "g's" or 30 times the acceleration due to gravity (9.8 m/s^2).

First, let's convert the acceleration from "g's" to m/s^2:
Acceleration (a) = 30 g's * 9.8 m/s^2/g ≈ 294 m/s^2

Next, we need to determine the mass of the body. This can vary, but for the sake of a general calculation, let's assume a mass of 70 kg.

Now, we can calculate the force:
Force (F) = mass (m) * acceleration (a)
= 70 kg * 294 m/s^2
≈ 20580 N (Newtons)

Therefore, the body would have to withstand a force of approximately 20580 Newtons during deceleration.

To calculate the distance traveled if the car was initially traveling at 90 km/hr, we can use the equation for distance (d) covered during deceleration:

d = (v^2 - u^2) / (2a)

Where:
d = distance
v = final velocity (0 m/s, as the car comes to a stop)
u = initial velocity (90 km/hr)

First, let's convert the initial velocity from km/hr to m/s:
Initial velocity (u) = 90 km/hr * (1000 m/1 km) * (1 hr/3600 s)
= 25 m/s

Now, let's plug the values into the equation and solve for distance:

d = (0^2 - 25^2) / (2 * 294)
= -625 / (2 * 294)
≈ -1.067 m

The negative value indicates that the car would have traveled 1.067 meters in the opposite direction it was moving before coming to a stop.

Therefore, when decelerating at 30 "g's", the car would have traveled approximately 1.067 meters in the opposite direction when initially traveling at 90 km/hr.