A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.
let L = wavelength, A = amplitude and w = angular frequency
max particle velocity = w A
wave speed = 2 pi w L
ratio (part speed)/(wave speed)
= A/(2 pi L)
Note that the ratio is independent of wave speed, w and cord tension. It would have been necessary to know these parameters to compute either speed.
Can you please relook at the question , the answer I get using the equation you provided did not work .Thank you anyway
A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.
The answer I got is 0.14979288 ( using A/(2 pi L) )
frequency*wavelength=wavespeed
w/2PI * L= wL/2PI
check that.
Thanks Bob. I put the 2 pi in the wrong place.
Thanks alot guys :)
To find the ratio of the maximum particle speed to the wave speed, we need to know the wave speed. The wave speed is given by the formula:
wave speed = frequency * wavelength
Since the frequency is not given, we need to find it using the formula:
frequency = wave speed / wavelength
Let's calculate the frequency:
frequency = wave speed / wavelength
Given that the wavelength is 3.4 cm, we still don't have the wave speed value.
Therefore, we cannot determine the ratio of the maximum particle speed to the wave speed without knowing the wave speed.