4x+4y=56

3x-16y=-91 slove by using systems of elimination multiply

I recommend multiply the first equation by 4. Then add the two equations. You should get then

19x+0y=4*56 -91

first equation times 4, then add to the second

19x = 133
x = 7

sub back into first
28 + 4y = 56
4y = 28
y = 7 , so x=7 and y=7

To solve the system of equations using the elimination method by multiplying, follow these steps:

Step 1: Choose one of the equations and multiply it by a constant in such a way that the coefficients of one of the variables in both equations have opposite signs. This will allow you to eliminate one variable when you add or subtract the equations.

Let's choose the second equation and multiply it by 4:
4 * (3x - 16y) = 4 * (-91)
12x - 64y = -364

Step 2: Now, let's write down the two equations with the resulting multiplication:
4x + 4y = 56
12x - 64y = -364

Step 3: Add or subtract the two equations to eliminate one variable. In this case, we can eliminate the variable 'y'.

(4x + 4y) + (12x - 64y) = 56 + (-364)
16x - 60y = -308

Step 4: Simplify the equation obtained in Step 3.

16x - 60y = -308

Step 5: Solve the resulting equation for the remaining variable. In this case, we can solve for 'x'.

16x = -308 + 60y
16x = 60y - 308
x = (60y - 308)/16
dividing both sides by 16:

x = 3.75y - 19.25

Once you have the value of 'x' in terms of 'y', you can substitute this expression into any of the original equations to solve for 'y'. Let's substitute it into the first equation:

4x + 4y = 56
4(3.75y - 19.25) + 4y = 56
15y - 77 + 4y = 56
19y - 77 = 56
19y = 56 + 77
19y = 133
y = 133/19
y = 7

Now that we have the value of 'y', we can substitute it back into the expression for 'x':

x = 3.75y - 19.25
x = 3.75(7) - 19.25
x = 26.25 - 19.25
x = 7

The solution to the system of equations is x = 7 and y = 7.